I would like to ask this circuit, why is there no voltage drop after the op amp and the diode? I haven't understood, is it necessary to have a voltage drop of about 0.3V to turn on the diode? Shouldn't the input positive Xuanbo be below 0.3V when output?
Harris Posté sur July 2, 2020
No, the feedback resistor is behind the diode, and the output is proportional to the input.
Julien Posté sur July 2, 2020
Precise rectifier circuit, freight and triode.
Marlene Posté sur July 2, 2020
This is caused by the virtual short of the op amp, and you will know more about the calculation method of the op amp.
